Clocked In Punched Out

given:
segment AD bisects segment BC
segment BC bisects segment AD

prove:
ΔABM and ΔDCM are congruent

1. segment AD bisects segment BC 1. given
2. segment AM ≅ segment DM 2. when a segment is bisected, the two resulting segments are congruent
3. segment BC bisects segment AD 3. given
4. segment BM ≅ segment CM 4. when a segment is bisected, the two resulting segments are congruent
5. ∠AMB ≅ ∠CMD 5. vertical angles are congruent
6. ΔABM ≅ ΔDCM 6. SAS postulate (2, 4, 5)

Still got it.

6 Comments

  1. Anonymous 18 Feb 09 at 03:49

    you must be asian.
    i hated geometry…and proofs.

    Reply
  2. Sweet Titty Bo Bitty 18 Feb 09 at 04:27

    Niiiiiice. Geomking.

    Reply
  3. hugo 18 Feb 09 at 15:46

    oh my god you just brought me back to the 9th grade

    i hate you

    Reply
  4. John 18 Feb 09 at 20:35

    Is this only for Euclidean geometry?

    Reply
    1. Jon 19 Feb 09 at 01:06

      No, I can factor polynomials too.

      Reply
  5. garkahar 21 Feb 09 at 21:59

    the opposing angles is the only rule i remembered.

    Reply

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