given:
segment AD bisects segment BC
segment BC bisects segment AD
prove:
ΔABM and ΔDCM are congruent
1. segment AD bisects segment BC | 1. given |
2. segment AM ≅ segment DM | 2. when a segment is bisected, the two resulting segments are congruent |
3. segment BC bisects segment AD | 3. given |
4. segment BM ≅ segment CM | 4. when a segment is bisected, the two resulting segments are congruent |
5. ∠AMB ≅ ∠CMD | 5. vertical angles are congruent |
6. ΔABM ≅ ΔDCM | 6. SAS postulate (2, 4, 5) |
Still got it.
you must be asian.
i hated geometry…and proofs.
Niiiiiice. Geomking.
oh my god you just brought me back to the 9th grade
i hate you
Is this only for Euclidean geometry?
No, I can factor polynomials too.
the opposing angles is the only rule i remembered.